kalexander66
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Parallelogram WXYZ has vertices W(0, 0) , X(1, 2) , Y(4, 2) , and Z(3, 0) . The parallelogram is dilated, and the vertices of the image are W'(0, 0) , X'(2, 4) , Y'(8, 4) , and Z'(6, 0) . The center of dilation is the origin. What is the scale factor of the dilation? Enter your answer in the box. Parallelogram WXYZ was dilated by a scale factor of .

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musiclover10045

(0,0) is the origin of a graph, so both W and W' remain at the origin.

The other 3 vertices double in size:

If you multiply all the numbers in X, Y and Z by 2, they become the numbers in X', Y' and Z'.

X(1,2)  x 2 = (1*2,2*2) = X'(2,4)

Y(4,2) x 2 = (4*2, 2*2) = Y'(8,4)

Z(3,0) x 2 = (3*2, 0*2) = Z'(6,0)

That means the scale factor is 2

Answer:

The scale factor for this question is 2

Step-by-step explanation: