albertekanempe89z1
albertekanempe89z1
29-08-2018
Mathematics
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log√30 - log√6 + log√2
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konrad509
konrad509
29-08-2018
Assuming, it's decimal logarithm.
[tex] \log\sqrt{30}-\log\sqrt6+\log\sqrt2=\log\dfrac{\sqrt{30}\cdot\sqrt2}{\sqrt6}=\log \sqrt{10}=\dfrac{1}{2}\log 10=\dfrac{1}{2}\cdot 1=\dfrac{1}{2}
[/tex]
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