MrJonezy4561 MrJonezy4561
  • 28-08-2018
  • Mathematics
contestada

Give the equation of the circle centered at the origin and passing through the point -8 0

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Riia
Riia Riia
  • 06-09-2018

The equation of circle that passes through origin is given by

[tex] x^2 + y^2 = r^2 [/tex]

And the given circle passes through (-8,0).

Substituting -8 for x and 0 for y, we will get

[tex] (-8)^2 + 0^2 = r^2 \\ 64=r^2 \\ r=8 [/tex]

So the required equation of corcle is

[tex] x^2 + y^2 =64 [/tex]

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