heeblyjeeblies
heeblyjeeblies
29-02-2016
Mathematics
contestada
H(x)=-x^2-4 and I(x)=2x+3
H(I(s))
Respuesta :
apologiabiology
apologiabiology
29-02-2016
easy peasy
just subsitute I(x) for the x in the h(x) so
h(I(s))=-(2s+3)^2-4
distribute and simplify
h(I(s))=-(4s^2+12s+9)-4
h(I(s))=-4s^2-12s-9-4
h(I(s))=-4s^2-12s-13
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